Question

32. In Fig. 15.106, the area of segment ACB is (a) w (--(5)- • (-3) - (a) None of these 120 A B С Fig. 15.106​

Answer 1

Answer:

Answer

Given angle of arc = 120 degrees

radius of circle = 21 cm

Area of circle = π*r^2

=3.14*21*21

=1386 cm2

Area of Arc= (angle of arc/ 360)*area of circle

= (120 /360)*1386

=1386/3

=462 cm2

Area of triangle = a*b*sinx / 2

=21*21*sin(120) /2

=190.96 cm2

Area of segment = area of arc - area of triangle

=462 - 190.96

=271.04 cm2