Question

32
In the following nuclear reaction, calculate the
number of alpha and beta particles released.
228
Th
92
Pb 204
84
Pps:
A.
6a and 6B​

Answer 1

Answer:

I HOPE IT IS CORRECT.

Explanation:

α-decay

                 

Z

A

​  

X  

α

​  

 

Z−2

A−4

​  

Y

β-decay

                 

Z

A

​  

X  

β

​  

 

Z+1

A

​  

Y

Decrease in atomic mass will be caused only by  

α-decay

               

90

228

​  

Th  

xα,yβ

​  

 

83

212

​  

Bi

No. of alpha particles emitted (x) =  

4

228−212

​  

 

                                                   x = 4

No. of beta particles emitted (y) = 2x-(90-83)

                                                     = 8-7 = 1.

                                                  y = 1

Hence, 4α, 1β are emitted in the number reaction  

               

90

228

​  

Th→  

83

212

​  

Bi