32 it is very difficult
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Let initial velocity (u) = 600km/h
Acceleration (a) = +10km/h per second = 36000km/h²
Final velocity (v) = 1100 km/h
v = u + at
Plugging the respective values
1100 = 600 + 36000(t)
1100 - 600 = 36000t
Solving for t
t = 0.1388 hrs = 0.8333 minutes = 50 seconds
So time taken to reach barrier = 50 seconds
Acceleration (a) = +10km/h per second = 36000km/h²
Final velocity (v) = 1100 km/h
v = u + at
Plugging the respective values
1100 = 600 + 36000(t)
1100 - 600 = 36000t
Solving for t
t = 0.1388 hrs = 0.8333 minutes = 50 seconds
So time taken to reach barrier = 50 seconds
Answered by
2
Initial velocity =u=600km/h
Final velocity =v=1100km/h
acceleration =10km/h/s=600m/h^2
now,
a=v-u/t
t=v-u/a
t=1100-600/60
=500/600
=5/6
=50sec... ans
hope it helps plz Mark it as brainliest....
Final velocity =v=1100km/h
acceleration =10km/h/s=600m/h^2
now,
a=v-u/t
t=v-u/a
t=1100-600/60
=500/600
=5/6
=50sec... ans
hope it helps plz Mark it as brainliest....
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