Question

32. Lengths of the outer edges of a closed box are respectively 25 cm, 23 cm and 18 cm. If thickness of the wood be 2 cm, then find (1) the total internal surface and also find the cost of painting the internal surface at the rate of 50 paise per cm”, (ii) cost of the total wood at the rate of Rs 1 per cm. ​

Answer 1

Answer:

$Rs. \: 959$

Step-by-step explanation:

Since the thickness of the box is 2cm on all sides.

So, the internal length, breadth and height of the box are:

$(254) = 21cm, (23-4)</strong></p><p></p><p><strong>[tex](254) = 21cm, (23-4)= 21cm, (184) = 21cm.$

So, Total internal surface area of the box =

$= 2(399 +266 +294)cm²</p><p></p><p>= 2 × 959cm² = 1918cm²$

Cost of painting internal surface area

$Rs. \: \times \frac{50}{100} = Rs. \: 959$

Hope it helps! :)