Question

32 men are working on a project for 7 hours a day. They take 40 days to complete the
project. Now, assume that only 20 men are available for working 8 hours a day. In
how many days will these 20 men complete the work?​

Answer 1

Answer:

working hour required for finish the work is

=32×7×40=8960 hours

so when 20 men working 8 hour per day

20×8=160 hour working per day

working hour required for finish the work is 8960

then 20 men working 8 hour per day they complete the work in 8960/160=56 days

Answer 2

The number of days to be taken to complete the same piece of work is 56 days.

32 men are working on a project for 7 hours a day. They take 40 days to complete the project. Now, assume that only 20 men are available for working 8 hours a day.

We have to find the number of days to be taken by 20 men to complete the same work.

It can be solved using formula, N₁D₁H₁ = N₂D₂H₂

Where

• N indicates number of workers
• D indicates number of days
• H indicates the work done in hours per day

Here, N₁ = 32 , D₁ = 40 , H = 7 , N₂ = 20 , H₂ = 8

⇒ 32 × 40 × 7 = 20 × D₂ × 8

⇒ D₂ = 56 days

Therefore the number of days to be taken to complete the same piece of work is 56 days.