Question

32) Prove that : + −1/
−−1
= sec A + tan A
​

Answer 1

Answer:

secA+tanA

1

​  

−  

cosA

1

​  

=  

cosA

1

​  

−  

secA−tanA

1

​  

 

Study later

ANSWER

According to question,

secA+tanA

1

​  

−  

cosA

1

​  

=  

cosA

1

​  

−  

secA−tanA

1

​  

 

⟹  

secA+tanA

1

​  

+  

secA−tanA

1

​  

=2secA

Solving LHS,

⟹  

(secA+tanA)(secA−tanA)

secA−tanA+secA+tanA

​  

 

⟹  

sec  

2

A−tan  

2

A

2secA

​  

 

⟹  

1

2secA

​  

 

⟹2secA  =  RHS

Hence proved

Step-by-step explanation:

Answer 2

Step-by-step explanation:

2 ex p I hope it helps you