Question

32) Show that there is only one line which
passes through B(5,5) and the sum of
whose intercept is zero.​

Answer 1

Answer:

solved

Step-by-step explanation:

sum of   intercepts = zero.​

let the intercepts be  a , -a

x/a - y/a = 1

5/a - 5/a ≠ 1

report

no line satisfies the conditions given

Answer 2

The equation of the line in intercept form is

$\frac{x}{a}+\frac{y}{b}=1$

Given that the sum of the intercept is zero

Therefore,

$a+b=0$

$\implies b=-a$

And, the line passes through $(5,5)$

Thus,

$\frac{5}{a}+\frac{5}{-a}=1$

or, $0=1$

Which is not possible.

Thus no such line exists.

Another case can be that the sum of the intercepts will be zero when both the intercepts are zero

In that case the line will pass through origin

Equation of line passing through origin and also through the point (5,5) is

$\boxed{y=x}$

Hope this helps.

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