Question

32. The maximum value of Fwhich can be applied on the system shown in figure so that both blocks move together
with same acceleration is
M₂
M
F
(Smooth surface)​

Answer 1

Answer:

f=m*a

a=m/F

f=u(m+m')a

so that (m+m')

Explanation:

Answer 2

Answer:

F=u(m1+m2)g

Explanation:

for m2 block friction acts towards right and acceleration is towards same side so

fr=ma

uN=m2a

um2g=m2a

a=ug

now for total system acceleration is same so

f=ma

f=u(m1+m2)g as acceleration a= ug