Question

32) The measure of all angles of a parallelogram if one angle is 24° less than twice the smallest angle are *

60°, 60°,120° , 120°

65°, 60°,120° , 120°

68°, 68°,112° , 112°

45°, 45°,120° , 120°

​

Answer 1

Answer:

68,68,112,112

Step-by-step explanation:

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Answer 2

$\color{red}{68°, 68°,112° , 112°}$

Step-by-step explanation:

Let the smaller Side x and larger side be

2x - 24 :-

In Parallelogram Opposite sides are equal and sum of adjacent sides is 180.

Therefore :-

x and 2x - 24 are adjacent Angles :-

Thus :-

$2x - 24 + x = 180 \\ 3x - 24 = 180 \\ 3x = 180 + 24 \\ 3x = 204 \\ x = \frac{204}{3} \\ \boxed{x = 68°}$

Thus the angles are :-

i) <A = x = 68

ii)<C = <A = 68

iii)<B =) 2x - 24 =112

iv)<D = <B = 112

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