Question

32. The median of the distribution given below is 14.4. Find the values of x and y, if the total
frequency is 20.
Class-interval
06
6-12
12-18
18–24
2430
Frequency
4
1
х
5
y
[NCERT EXEMPLAR]​

Answer 1

Answer:

Answer

Class IntervalFrequencymidpoint (x)Comm frequecy0-64346-12x94+x12-185159+x18-24y219+x+y24-3012710+x+yTotal20

∑f=20

x+y=10−−−−−−−−−−(1)

Median is 14.4

S0, Median class is 12−18

Median =L+f2n−C×w

So 14.4=12+5220−(4+x)×6

14.4×5=60+(10−4−x)×6

72=60+60−24−6x

6x=120−24−72

6x=120−96

6x=24

x=4

from eq (1)

4+y=10⇒y=6