Question

32. The numerator of a certain fraction is 3 times the denominator. If the numerator is
decreased by 1 and the denominator is increased by 2, the value of the resulting fraction
is 5/2. Find the original fraction.​

Answer 1

Answer:

let the denominator be x

and numerator be 3x

A.C.T

3x - 1/x + 2 = 5/2

on cross multiplication

6x - 2 = 5x + 10

x = 12

hence the fraction will be 36/12 = 3/1

PLZ MARK THIS AS THE BRAINLIEST

Answer 2

Answer:

• The original fraction is 36/12.

Given:

• The numerator of a certain fraction is 3 times the denominator.

• If the numerator is decreased by 1 and denominator is increased by 2, the value of the resulting fraction is 5/2.

To find:

• The original fraction.

Solution:

Let the denominator of a fraction be x.

According to the first condition.

=> Numerator = 3x

Fraction = 3x/x

According to the second condition.

=> (3x - 1) / (x + 2) = 5/2

=> 2 (3x - 1) = 5 (x + 2)

=> 6x - 2 = 5x + 10

=> x = 12

Denominator = 12 and

numerator = 3 (12) = 36

The original fraction is 36/12.