Physics, asked by sssbhat63, 4 months ago

32. The power of a water jet flowing through
office of radius 10 cm with a velocity 5 met
A 196 watt
C. 19.6 watt
B. 1960 watt
D. 1.96 watt​

Answers

Answered by sidratul1
0

Answer:

1962 W

Explanation:

Power = KE imparted to water in one second.

= 1 2 m v 2 t

= 1 2 × m a s s  f l o w i n g  p e r  s e c o n d × v 2 = 1 2 × ( A v ρ ) v 2

=1 2 A v 3 ρ  = 1 2 × π ( r 2 × v 3 ρ )

= 1 2 × π × ( 10 100 ) 2 × 5 3 ×1000 J / s = 1962  w a t t .

Hence, the power of a water jet flowing through the orifice is 1962 W.


sssbhat63: but what is AVP ?
sssbhat63: and my second question is if formula of K.E is 1/2 mv2 then why you have wrote - 1/2mv2/t?
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