Question

32. The shadow of a tower standing on a level ground is found to be 40 m longer when theSun's altitude is 45° than when it is 60°. Find the height of the tower.​

Answer 1

Answer:

Ssssssssssssooo9oooooorrrrrrrrryyyyyyyyyyyyyyyyyyyy

Answer 2

Answer:

In △ABD,

tan60  

o

=  

BD

AB

​  

 

3

​  

=  

x

h

​  

 

∴   x=  

3

​  

 

h

​  

                ------- ( 1 )

Now in △ABC,

tan30  

o

=  

BC

AB

​  

 

⇒    

3

​  

 

1

​  

=  

x+40

h

​  

 

⇒  x+40=  

3

​  

h

∴    

3

​  

 

h

​  

+40=  

3

​  

h          [  From equation ( 1 ) ]

⇒  h+40  

3

​  

=3h

⇒  2h=40  

3

​  

 

∴  h=20  

3

​  

m

∴  The height of a tower is 20  

3  m.

​  

Step-by-step explanation: