Question

32) The sum of three consecutive numbers is 123. Find the numbers.

​

Answer 1

Suppose first number is 'n'.

Then, 2nd consecutive number will be (n+1)

And, 3rd consecutive number will be (n+2).

According to question,

n + (n+1) + (n+2) = 123

3n + 3 = 123

n + 1 = 123/3

n +1 = 41

n = 41 -1

n = 40......●

Thus, 1st number = 40

2nd number = 41

3rd number = 42.

●●●●●●●●●●●●●●●●●●

Hope it was helpful.