(32.) The sum of three consecutive odd numbers is 972. Find the numbers.
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Answer:
323 , 324, 324
Step-by-step explanation:
let 1st be x
let 2nd be x+1
let 3rd be x+2
ATQ:-
x+(x+1)+(x+2)=972
x+(x+1)+(x+2)=9723x+3=972
x+(x+1)+(x+2)=9723x+3=9723x=972-3
x+(x+1)+(x+2)=9723x+3=9723x=972-3x=969/3
x+(x+1)+(x+2)=9723x+3=9723x=972-3x=969/3x=323
- ●x=323
- x=323●x+1=324
- x=323●x+1=324●x+2=325
to check:-
323+324+325=972
972=972
LHS=RHS
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