Question

32. Two blocks of unequal masses are moving with
same kinetic energy. They are brought to rest by
applying same retarding force. Then
(1) Heavier block will come to rest in shorter
distance
(2) Lighter block will come to rest in shorter
distance
(3) Both will come to rest in same distance
(4) None of the above​

Answer 1

Answer:

(2) Lighter block will come to rest in shorter

distance

Explanation:

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Answer 2

(3) Both will come to rest in same distance

Explanation:

Given that:

$KE_h=KE_l$

• $\frac{1}{2} m_h.v_h^2=\frac{1}{2} m_l.v_l^2$

• $F_h=F_l$

where the subscripts h & l are for heavier & lighter mass respectively.

Now, form the work energy equivalence, the work done to stop the bodies:

$F_h.d_h=\frac{1}{2} m_h.v_h$ ......................................................(1)

$F_l.d_l=\frac{1}{2} m_l.v_l$ ..........................................................(2)

divide eq. (1) by (2)

$\frac{d_h}{d_l} =1$

$d_h=d_l$

TOPIC: kinetic energy, work-energy equivalence.

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