Math, asked by anayaali1, 2 months ago

32 x 20
53 - 3/2013
Plz help me solve this . Btw in the question this part / is a square root

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Answers

Answered by jgkanishka
3

Answer:

32 \times 20 = 640

53 - 3 \div 2013 = 52.998509687

640 \div 52.998509687 = 12.0758112592

I think this only

Answered by Anonymous
17

Question :-

Simplify -

\sf \dfrac{3^2 \times \sqrt{20}}{5^3 - \sqrt[3]{2013}}

Answer :-

\implies\sf \dfrac{3^2 \times \sqrt{20}}{5^3 - \sqrt[3]{2013}}

\implies\sf \dfrac{3 \times 3 \times \sqrt{5 \times 2 \times 2}}{5\times 5 \times 5 - \sqrt[3]{3 \times 11 \times 61}}

\implies\sf \dfrac{9 \times 2\sqrt{5}}{125 - \sqrt[3]{3 \times 11 \times 61}}

\implies\sf \dfrac{9 \times 2\sqrt{5}}{125 - \sqrt[3]{3} \times \sqrt[3]{11} \times \sqrt[3]{61}}

\implies\sf \dfrac{18 \sqrt{5}}{125 - 12.62} \:\:( approx )

\implies\sf \dfrac{18 \times 2.23}{125 - 12.62}

\implies\sf \dfrac{40.14}{112.38}

\implies\sf 0.35

Additional information :-

\begin{gathered}\boxed{\begin{minipage}{5 cm}\bf{\dag}\:\:\underline{\text{Law of Exponents :}}\\\\\bigstar\:\:\sf\dfrac{a^m}{a^n} = a^{m - n}\\\\\bigstar\:\:\sf{(a^m)^n = a^{mn}}\\\\\bigstar\:\:\sf(a^m)(a^n) = a^{m + n}\\\\\bigstar\:\:\sf\dfrac{1}{a^n} = a^{-n}\\\\\bigstar\:\:\sf\sqrt[\sf n]{\sf a} = (a)^{\dfrac{1}{n}}\end{minipage}}\end{gathered}

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