320 Mitra lambi train Ek Pol Ko 40 kilometre per hour ki gati Se Pyar Karti Hai to wea Pol Par karne me kitna Samay Legi
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let the pole be of negligible length.
thus, the train mainly covers the distance of self length.
so,
speed = distance/time
=> 40000m/hr = 320/t (let the time taken be t)
hence, 125hr = 1/t
hence, t= 0.008 hr
= 0.008 X 60 X 60 sec
= 28.8 sec
thus, the train mainly covers the distance of self length.
so,
speed = distance/time
=> 40000m/hr = 320/t (let the time taken be t)
hence, 125hr = 1/t
hence, t= 0.008 hr
= 0.008 X 60 X 60 sec
= 28.8 sec
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