Math, asked by jaspreetkaur290, 11 months ago

321,322,321,325,317,326,299,?​

Answers

Answered by sharonr
1

The missing term in 321,322,321,325,317,326,299,? is 315

Solution:

Given, series is 321, 322, 321, 325, 317, 326, 299 , ?

We have to find the missing term of the above series.

If we observe the given series, it can also be written as

321,321+1^{2}, 322-1^{3}, 321+2^{2}, 325-2^{3}, 317+3^{2}, 326-3^{3}

So, the next term would be 299+4^{2}=299+16=315

Hence, the missing term is 315.

Answered by parveen17179
0

Answer:

315 is a correct answer of this question

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