Question

322. In the given fig. ZOAB = 30° and LOCB = 57º. Find LABC
130
A
B
С​

Answer 1

Answer:

33°

Step-by-step explanation:

Let perpendicular intersection be at point D

∠BCO=57°

and ∠BDC = 90°

∠ABC = 180°-90°-57°

∠ABC = 180°-147°

∠ABC = 33°

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