Question

3²41
qx-2 solve for a
$3 ^{x + 1} = 9 ^{x - 2} find the value ofx$
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Answer 1

SOLUTION :

$\sf \: 3 ^{x + 1} = 9 ^{x - 2}$

$\sf \implies \: {3}^{x + 1} = {9}^{x - 2}$

$\sf \implies \: {3}^{x + 1} = {3}^{2(x - 2)}$

$\sf \implies \: x + 1 = 2x - 4$

$\sf \implies x = \frac{4}{3}$