Math, asked by azunglaSPongen, 1 month ago

= 3281.25
tercise 15.1
The length of a rectangular-shaped label is 1 centimetre more than twice the width. The perimeter
- 110 centimetres. Find the area of the rectangle.​

Answers

Answered by Atlas99
13

666cm².

Step-by-step explanation:

Let,

Width = x.

Length = 1 + 2x.

Perimeter of rectangle = 2(l + w).

Putting known values in the formula

➻ 110 = 2(1+2x + x).

Adding 2x and x

➻ 110 = 2(1+3x).

Multiplying 1 and 3x by 2

➻ 110 = 2 + 6x.

Bringing 2+6x to LHS

➻ 2 + 6x = 110.

Subtracting 2 from 110

➻ 6x = 110 - 2.

It can be written as

➻ 6x = 108.

Dividing 108 by 6 to find the value of x

➻ x = 108/6.

On cancelling we get

➻ x = 54/3.

Bringing this fraction into the simplest form and again cancelling

➻ x = 18.

Therefore,

Width = x = 18cm.

Length = 1+2x = 1+2(18) = 1+36 = 37cm.

Now, calculating area of the rectangle

Area of rectangle = Length × Width

Area of rectangle = 18 × 37

Area of rectangle = 666cm².

Answered by YourHelperAdi
8

To Find :

The Area of the rectangle given .

Given :

  • Length of Rectangle is 1 centimeter more than twice of the width .
  • Perimeter of the rectangle = 110 cm

Formula To be Applied :

We will here use these formula related to rectangle :

1] Perimeter of rectangle:

P = 2(l+b)

2] Area of rectangle:

Area = l×b

Let's Assume :

Let's Assume that the breadth of the rectangle is 'x'.

So, Length = 1+2breadth

or, Length = 1+2x = 2x+1

Process:

We will first Assume the length and breadth of the rectangle. Then with the formula of perimeter of rectangle, we will find the value of x and then find the length and breadth.

Through these values, we can find the area of the rectangle.

Solution :

Breadth = x

Length = 2x+1

So, perimeter = 2(l+b)

 \implies \tt{p = 2(x + 2x + 1)}

 \implies \tt{110 = 2(3x + 1)}

 \implies \tt{110 = 6x + 2}

 \tt{ \implies 6x = 110 - 2}

 \implies \tt{x =  \frac{108}{6} }

 \implies \tt{x = 18}

Hence, Breadth = x = 18 cm

Length = 2x+1 = 37 cm

Hence, Area = l×b

 \implies \tt{area = 18 \times 37}

 \red{ \underline{ \boxed{ \tt{ \therefore area = 666 \: c {m}^{2} }}}}

Hence, Area of rectangle = 666 cm ²

__________________________

Additional Information :

These are some formulas related to mensuration:

  • Area of rectangle = l×b
  • Area of Square = Side²
  • Area of Circle = (pi)r²
  • Area of Triangle (Simple) = ½×base×Hieght
  • Area of triangle (Heron's)

 \tt{area =  \sqrt{s(s - a)(s - b)(s - c)}}

  • Perimeter of rectangle = 2(l+b)
  • Perimeter of Square = 4×side
  • Perimeter of circle = 2(pi)r
  • Perimeter of triangle = a+b+c

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