Question

32a^2x^3-8b^2x^3-4a^2y^3+b^2y^3​

Answer 1

Answer:

[(2x-y)(4x^2+y^2+2xy)][(2a-b)(2a+b)]

Step-by-step explanation:

32a^2x^3-8b^2x^3-4a^2y^3+b^2y^3​

=8x^3(4a^2-b^2)-y^3(4a^2-b^2)

=(8x^3-y^3)(4a^2-b^2)

=[(2x)^3-y^3][(2a)^2-b^2]

=[(2x-y)(4x^2+y^2+2xy)][(2a-b)(2a+b)]

Answer 2

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