Question

32a^3+108b^3 factorise​

Answer 1

Answer:

= 4(8a^3+27b^3)

= 4((2a^3)+(3b^3)) (using a^3+b^3=(a+b)(a^2-ab+b^2)

= 4((2a+3b)((2a^2)-2a×3b+(3b^2))

= 4(2a+3b)(4a^2-6ab+9b^2)

Step-by-step explanation:

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