Question

32a3 +108b3 =___________
please tell the answer like in the photo method​

Answer 1

Answer:

$32 {a}^{3} + 108 {b}^{3} \\ = 4(8{a}^{3} + 27 {b}^{3} ) \\ = 4 \{(2a)^{3} + (3b)^{3} \} \\ = 4 \{(2a + 3b)^{3} - 3 \times 2a \times 3b(2a + 3b)\} \\ = 4 \{(2a + 3b)^{3} - 18ab(2a + 3b)\} \\ = 4 (2a + 3b)\{(2a + 3b)^{2} - 18ab\} \\ = 4 (2a + 3b)\{4 {a}^{2} + 9{b}^{2} + 12ab \: - 18ab\} \\ = 4 (2a + 3b)(4 {a}^{2} + 9{b}^{2}-6ab)</p><p>\\ = (8a + 12b)(4 {a}^{2} -6ab + 9{b}^{2})$

Answer 2

Answer:

Here you go!! HOPE IT HELPS!!