32A76589B is divisible by 72 what is the value of A+B
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7
Answer:
10
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Given 32A76589B is divisible by 72 what is the value of A+B
Given 32A76589B is divisible by 72
So it should be divisible by 8 also.
Now last 3 digits should be divisible by 8
So 89 B should be divisible by 8
So B = 6 since 896 is divisible by 8
Also the given number is divisible by 9 also
Sum of all digits must be a multiple of 9
So 3 + 2 + a + 7 + 6 + 8 + 9 + 6
41 + a
41 + 4 = 45 is divisible by 9
A = 4
so a + b = 6 + 4 = 10
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0
Answer:
14
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