Question

32ab^4-162a
Exam Pls help​

Answer 1

The factorisation of 32a$b^4$ - 162a is equa to $2a(4b^2+9)(2b+3)(2b-3)$.

Step-by-step explanation:

We have,

32a$b^4$ - 162a

To find, the factorisation of 32a$b^4$ - 162a = ?

∴ 32a$b^4$ - 162a

Taking '2a' as common, we get

= 2a(16$b^4$ - 81)

$= 2a[(2b)^2)^2 - (3^2)^2]$

Using the algebraic identity,

$a^{2}-b^{2}=(a+b)(a-b)$

$=2a((2b)^2+3^2)((2b)^2-3^2)$

$=2a(4b^2+9)((2b)^2-3^2)$

Again, using the algebraic identity,

$a^{2}-b^{2}=(a+b)(a-b)$

$=2a(4b^2+9)(2b+3)(2b-3)$

∴ The factorisation of 32a$b^4$ - 162a = $2a(4b^2+9)(2b+3)(2b-3)$

Thus, the factorisation of 32a$b^4$ - 162a is equa to $2a(4b^2+9)(2b+3)(2b-3)$.

Answer 2

ANSWER:

32ab⁴-162a

2a(16b⁴-81)

2a[(4b)²-(9)²]

2a[(4b+9)(4b-9)]

2a[(4b+9)((2)²-(9)²)

2a[(4b+9)((2+9)(2-9)]

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