32ab4-162a ...... factorise
Answers
The factorisation of 32ab^4b
4
- 162a is equa to 2a(4b^2+9)(2b+3)(2b-3)2a(4b
2
+9)(2b+3)(2b−3) .
Step-by-step explanation:
We have,
32ab^4b
4
- 162a
To find, the factorisation of 32ab^4b
4
- 162a = ?
∴ 32ab^4b
4
- 162a
Taking '2a' as common, we get
= 2a(16b^4b
4
- 81)
= 2a[(2b)^2)^2 - (3^2)^2]=2a[(2b)
2
)
2
−(3
2
)
2
]
Using the algebraic identity,
a^{2}-b^{2}=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
=2a((2b)^2+3^2)((2b)^2-3^2)=2a((2b)
2
+3
2
)((2b)
2
−3
2
)
=2a(4b^2+9)((2b)^2-3^2)=2a(4b
2
+9)((2b)
2
−3
2
)
Again, using the algebraic identity,
a^{2}-b^{2}=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
=2a(4b^2+9)(2b+3)(2b-3)=2a(4b
2
+9)(2b+3)(2b−3)
∴ The factorisation of 32ab^4b
4
- 162a = 2a(4b^2+9)(2b+3)(2b-3)2a(4b
2
+9)(2b+3)(2b−3)
Thus, the factorisation of 32ab^4b
4
- 162a is equa to 2a(4b^2+9)(2b+3)(2b-3)2a(4b
2
+9)(2b+3)(2b−3)
Step-by-step explanation:
Its may helps you I hope.
