Question

32cc of hydrogen diffuses through a fine hole in 1 minute. what volume of co2 will diffuse in 1 minute under the same conditions

Answer 1

Answer:- 6.8 cc.

Solution:- From Graham's law of diffusion rates, " Rate of diffusion of a gas is inversely proportional to the square root of it's molar mass."

$\frac{r_1}{r_2}=\sqrt{\frac{M_2}{M_1}}$

rate of effusion is the volume of the gas effused in a unit time. So, let's replace rate by $\frac{volume}{time}$ . The formula could also be written as:

$\frac{\frac{v_1}{t_1}}{\frac{v_2}{t_2}}=\sqrt{\frac{M_2}{M_1}}$

Time of effusion is same for both the gases. So, the formula becomes:

$\frac{v_1}{v_2}=\sqrt{\frac{M_2}{M_1}}$

Molar mass of hydrogen is 2 gram per mol and 44 gram per mol for carbon dioxide. Let's plug in the values in the above formula:

$\frac{32cc}{v_2}=\sqrt{\frac{44}{2}}$

$\frac{32cc}{v_2}=4.69$

$v_2=\frac{32cc}{4.69}$

$v_2$ = 6.8cc

So, in one minute, 6.8 cc of carbon dioxide would be effused.