Question

32g O2,2gH2 and 28gN2 at S.T.P occupy separately a volume of​

Answer 1

Answer:

Hydrogen exist as H

2

and oxygen as O

2

1 mole of all gases occupy 22.4 L volume at NTP

Moles in 2 g hydrogen =

molar mass

mass

=

2

2

=1 mol=22.4 L

Moles in 32 g oxygen =

molar mass

mass

=

32

32

=1 mol=22.4 L

Total volume occupied =22.4+22.4=44.8 L

hope it helps.. !!