32g of O2 have the same number of molecules as in?
Answers
Answer:
Explanation:
1 mole has 32 g of O2 ----- 6 x 10 ²³
therefore it has same no. of molecules as in avagardo number
Correct question:
32 g of O₂ have the same number of molecules as in
a) 16 g of CO
b) 28 g of N₂
c) 14 g of N₂
d) 1.0 g of H₂
Solution:
Given:
Mass of O₂ = 32 g
To find:
No of molecules in the given compound
Calculation:
Mass of 1 molecule of O₂ = 2(molecular mass of O)
= 2(16) = 32 g
Number of molecules = (Mass / Molecular mass)×6.023×10²³
=> n = (32/32)×6.023×10²³
=> n = 6.023×10²³
a) 16 g of CO
Number of molecules = (Mass / Molecular mass)×6.023×10²³
=> n = (16/38)
=> n = 2.536×10²³
b) 28 g of N₂
Number of molecules = (Mass / Molecular mass)×6.023×10²³
=> n = (28/28)×6.023×10²³
=> n = 6.023×10²³
c) 14 g of N₂
Number of molecules = (Mass / Molecular mass)
=> n = (14/28)×6.023×10²³
=> n = 3.011×10²³
d) 1.0 g of H₂
Number of molecules = (Mass / Molecular mass)×6.023×10²³
=> n = (1/2)×6.023×10²³
=> n = 3.011×10²³
28 g of N₂ have same number of molecules as 32 g of O₂