Question

32g of sulphur (at. mass 32) contains6.022 X 10^22
6.023 X 10^22
6.023 X 10^24
6.023 X 10^23

Answer 1

Answer:

As both, O2 and S have same mass so 32 g of O2 contains same number of moles as 32 g of S.

So, they both have same number of molecules at NTP.

Therefore, 32 g of S contains 6.022×1023 atoms.