Question

32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide. What will be the amount of sulphur dioxide formed if 64g of sulphur is burnt in 32g oxygen? Name and state the law that governs your answer.

Answer 1

Answer:

96

Explanation:

conservation law of mass

Answer 2

Answer:

amount will be 64g only , just 32g of sulphur will be unreacted

Explanation:

case 1- 32g(sulphur)+32g(oxygen)=(sulphur di oxide) 64g

case 2- 64g+32g=?

in case 1, 32 g of sulphur requires 32g of oxygen

now in 2nd case only 32g of 64g of sulphur will be required to burn with 32g of oxygen to react and form sulphur dioxide , so the rest 32g will be unreacted in the second case

usually people will be thinking that it is conservation of mass , but it is law of definite proportion, as, only 32g + 32g= 64g of sulphur dioxide, the proportion  1:1 has to always be constant in the compound of 64g of sulphur dioxide or only 32g of sulphur and 32g of 02 helps to make 64g of sulphur di oxide