32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide. What will be the amount of sulphur dioxide formed if 64g of sulphur burnt in 32g of oxygen? Name and state the law that governs your answer.
Answers
Given:
32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide.
To Find:
Amount of sulphur dioxide formed if 64g of sulphur burnt in 32g of oxygen.
Solution:
It is given that, 32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide.
=> 32g of sulphur requires 32g of oxygen.
Now, we have 64g of sulphur to react with 32g of oxygen
But, 64g of sulphur will require 64g of oxygen.
=> Oxygen is limiting reagent.
=> Only 32g of sulphur will burn in 32g of oxygen to form 64g of sulphur dioxide.
Law of definite proportion & concept of limiting reagent is used.
Hence, 64g of sulphur dioxide is formed.
Given:
32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide.
To Find:
Amount of sulphur dioxide formed if 64g of sulphur burnt in 32g of oxygen.
Solution:
It is given that, 32g of sulphur burns in 32g of oxygen to form 64g of sulphur dioxide.
=> 32g of sulphur requires 32g of oxygen.
Now, we have 64g of sulphur to react with 32g of oxygen
But, 64g of sulphur will require 64g of oxygen.
=> Oxygen is limiting reagent.
=> Only 32g of sulphur will burn in 32g of oxygen to form 64g of sulphur dioxide.
Law of definite proportion & concept of limiting reagent is used.
Hence, 64g of sulphur dioxide is formed.