32g of sulphur diaoxide no. of moles and particle
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hey frnd.....
molar mass of sulphur dioxide (SO2) = 32 + (16×2) = 32+32 = 64 g/mol
1) moles = given mass / molar mass
= 32/64
= 0.5 moles
2) no of particles in 1 mole of SO2 = 6.022×10^23
so.....no of particles in 0.5 moles = 0.5 × 6.022×10^23
= 3.011 ×10^23
HOPE THIS HELP YOU ☺☺❤❤❤
molar mass of sulphur dioxide (SO2) = 32 + (16×2) = 32+32 = 64 g/mol
1) moles = given mass / molar mass
= 32/64
= 0.5 moles
2) no of particles in 1 mole of SO2 = 6.022×10^23
so.....no of particles in 0.5 moles = 0.5 × 6.022×10^23
= 3.011 ×10^23
HOPE THIS HELP YOU ☺☺❤❤❤
disha6086:
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