Question

32P beta-decays to 32S. Find the sum of the energy of the antineutrino and the kinetic energy of the β-particle. Neglect the recoil of the daughter nucleus. Atomic mass of 32P = 31.974 u and that of 32S = 31.972 u.

Answer 1

The answer is $1.862 MeV.$

Explanation:

In the question, it is given:

32P has the atomic mass, m(32P) = 31.974 u

32S has the atomic mass, m(32S) = 31.972 u

Daughter nucleus’ recoil is neglected.

The reaction can be given as below:

$\mathrm{p} 32 \rightarrow 1 \mathrm{vO}+\mathrm{S} 32+-1 \beta 0$

Energy of β-particle and antineutrino, $E=\left[m\left(^{32} p\right)\right.$

$\left.-m\left(^{32} s\right)\right] c^{2}$

$=(-31.972 u+31.974 u) c^{2}$

$=0.002 \times 931=1.862 \mathrm{MeV}$