Math, asked by guptamuskan1961, 11 months ago

32students play basketball and 25 student play volleyball. it is found that 13 student play both game .find the number of students playing at least one game​

Answers

Answered by venupillai
10

Answer:

No. of students playing at least one game = 44

Step-by-step explanation:

B = basketball; V = volleyball

n(B) = no of students playing only B

n(V) = no. of students playing only V

n(B∩V) = no. of students playing both B and V

Now:

32 students play basketball. Some of them could also be playing volleyball. Hence, the number of students playing only basketball will be 32 minus those that play both.

n(B) = 32 - 13 ............(Given that 13 play both games)

n(B) = 19

Similarly,

25 students play volleyball. Some of them could also be playing basketball. Hence, the number of students playing only volleyball will be 25 minus those that play both.

n(V) = 25 - 13

n(V) = 12

Thus, we have 19 students playing only B, 12 students playing only V and 13 students playing BOTH.

Clearly, the number of students that play at least one game is:

No. of students playing ONLY basketball +

No. of students playing ONLY volleyball +

No. of students playing BOTH

This can be given as:

n(B) + n(V) + n(B∩V)

= 19 + 12 + 13

= 44

See attached Venn Diagram to support understanding

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