Math, asked by ksrairscc, 7 months ago

((33)^2-(31)^2)^5/7=?

Answers

Answered by khushboovishal884
4

Answer:

32 is the answer

Step-by-step explanation:

 \\

(33 {}^{2}  - 31 {}^{2}  )power5 \div 7  \\  \\  \\  = 1089 - 961ka \: power \: 5 \div 7so \\  \\  = 128ka \: power \: 5 \div 7 \: it \: mean \\  \\  \\ 2 {}^{5 = 32}

32is \: the \: answer

Answered by Anonymous
2

\huge\red{Answer}

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☆☞ [ Verified answer ]☜☆

Step-by-step explanation:</p><p></p><p>\begin{gathered}\\\end{gathered}</p><p></p><p>\begin{gathered}(33 {}^{2} - 31 {}^{2} )power5 \div 7 \\ \\ \\ = 1089 - 961ka \: power \: 5 \div 7so \\ \\ = 128ka \: power \: 5 \div 7 \: it \: mean \\ \\ \\ 2 {}^{5 = 32}\end{gathered}(332−312)power5÷7=1089−961kapower5÷7so=128kapower5÷7itmean25=32</p><p></p><p>32is \: the \: answer32istheanswer</p><p></p><p>

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