Question

3³-2x²-5ax-8 and x³+ax²-12x-6 are divided by (x-2) and (x-3) leaves the remainder p and q. If q-p=10.find a.

Answer 1

Answer:

Step-by-step explanation:

f(x)=3³-2x²-5ax-8

f(x)=27-2ax²-5ax-8

    =-2ax²-5ax+19

g(x)=x-2

f(2)=-2*a*(2)²-5*a*2+19

    =-8a-10a+19

    =-18a+19=p

f(x)=x³+ax²-12x-6

g(x)=x-3

f(3)=(3)³+a*(3)²-12*3-6

    =27+9a-36-6

    =9a-15=q

now,

q-p=10

(9a-15)-(-18a+19)=10

9a-15+18a-19=10

27a-34=10

27a=44

a=44/27

  =1.62