Question

3³ – 4s²+5s-2 / 5rs +r² +rs³ r =6 s =3​

Answer 1

Answer:

$= \frac{{s}^{3} - 4 {s}^{2} + 5s - 2}{5rs + {r}^{2} + r {s}^{2} } \\ = \frac{{3}^{3} - 4( {3}^{2} ) + 5(3) - 2}{5(6)(3) + {6}^{2} + 6 ({3}^{3} ) } \\ = \frac{27 - 36 + 15 - 2}{90 + 36 + 162} \\ = \frac{4}{288} \\ = \frac{1}{72}$