Question

33. 62 + y = (6-y)2 + 20, तो y का मान क्या है ?​

Answer 1

Answer:

-0. 54

Step-by-step explanation:

33.62+y=12-2y+20

33.62+3y=32

3y=32-33.62

3y=-1.62

y=1.62÷3

y=-0.54

Answer 2

Step-by-step explanation:

62 + y = (6-y)^2 + 20

62+y = 36-12y+y^2+20

62+y = 56-12y+y^2

y^2-13y-6=0

a=1,b= -13 and c= -6

-b+√(b^2-4ac) -b-√(b^2-4ac)

y = -------------------- and --------------------

2a 2a

13+√[169-4(1)(-6)] 13-√[169-4(1)(-6)]

= ------------------------ and ------------------------

2 2

13+√193 13-√193

= ------------- and --------------

2 2