Question

33)
A block of mass 5 kg lies on a rough horizontal table. A force of 19.6 N is enough to keep
the body sliding a uniform velocity. The coefficient of sliding friction is :
a) 0.2
b) 0.4
c) 0.5
d) 0.8
​

Answer 1

Answer:

b) 0.4

Step-by-step explanation:

frictional force f = coeff. of sliding friction friction * normal reaction

f= kN

k=f/N

N= mg= 5*10=50N

k=19.6/50

k=0.392

k=0.4