Question

33) A body is vertically thrown up with a velocity of 78.4 m/s.
(a) How much height it will rise?
(b) How much time it will take to return to its point of projection? (Given g = 9.8ms).​

Answer 1

Step-by-step explanation:

u= 78.4 m/s

v=0

v

$v {}^{2} = u {}^{2} + 2as \\ 0 {}^{2} = (78.4) {}^{2} + 2( - 9.8) \times s \\ 0 = 6146.56 - 19.6s \\ 19.6s = 6146.56 \\ s = 6146.56 \div 19.6 \\ s = 313.6m$