Question

33. A neutron (mass 1.67 x 10 kg) moving at a speed
of 1.0 x 108 ms collides with a deutron (mass
3.34 x 10-27 kg) at rest and sticks to it. Find the speed
of the composite particle triton. Ans. 3.33 x 10²ms-1.​

Answer 1

Answer:

using low of moment conservation

moment before collision= moment after collision

m1v1=m2v2 -------------------eq1

moment before collision= m1v1

= 1.67*(10^-27) kg*1.0*(10^8) m/s -------------eq2

moment after collision = m2v2

so m2= mass of neutron and mass of deuteron

and velocity is v2

m2v2= (1.67*(10^-27) +3.34*(10^-27))kg*v2 m/s

m2v2= 5.01*(10^-27) kg* v2 m/s -------------eq3

from eq 1,2,3

1.67*(10^-27) kg* 1.0*(10^8) m/s = 5.01*(10^-27)kg *v2 m/s

(1.67*10^8)/(5.01) m/s = v2

v2 =8.3667 *(10^8) m/s