Physics, asked by nikhilshinde3234, 10 months ago

33. A particle with acceleration a = -kv (where k is
constant and v is velocity) crosses origin with
velocity Voi^. Velocity of the particle at point (L,0) is
(a) Vo- kL .
(b) v + kL
(c) √Vo^2-kL^2
(d)√Vo^2+kL^2​

Answers

Answered by Anonymous
1

a = vdv/dx

-kv = vdv/dx

dv = -kdx

Integrating on both sides

v= -kx

Putting limits with x initual value =0, final value = L

v- Vo = -kL

v = Vo-kL

Explanation:

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