Physics, asked by sahanareddyreddy003, 2 months ago

33. A stone is tied to one end of a string and whirled in a horizontal circle of radius 1 m at 20 revolutions

per minute. Calculate the angular velocity and linear speed of the stone. Also find the centripetal

acceleration.

34. A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required

by the body and the work done by the applied force.

35. If the earth has a mass 9 times and radius twice of the planet mars, calculate the minimum speed

required by a rocket to pull out of the gravitational force of Mars. Escape speed for an object on the

surface of the earth is 11.2 kms-1

.​

Answers

Answered by anushay84011
2

Answer:

Given length of the string l= 1 m also angular velocity ω=

44

22

revolution/second.

We know linear velocity v=ω×r

Thus velocity v=

44

22

×1=0.5 m/s

And we know centripetal or radial acceleration a

c

=

r

v

2

Thus a

c

=0.25m/s

2

2- Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s

3- Given: Me = 9 Mm, and Re = 2 Rm, ve (escape speed on surface of Earth) = 11.2 km/s

Let Vm be the speed required to pull out of the gravitational force of mars.

We know that

and

Dividing, we get

⇒ vm = 5.3 km/s

Answered by Mysteryboy01
1

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