Question

33. A stone is tied to one end of a string and whirled in a horizontal circle of radius 1 m at 20 revolutions

per minute. Calculate the angular velocity and linear speed of the stone. Also find the centripetal

acceleration.​

Answer 1

Explanation:

Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s

Answer 2

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