Question

33) A TV reporter was given a task to prepare a report on the rainfall of the city Dispuro
year. After collecting the data, he analyzed the data and prepared a report on the rainfall of the city. Using this report
he drew the following graph for a particular time period of 66 days
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60
Based on the above graph, answer the bllowing questions:
Identify less than type og and more than type ogive from the given graph,
() Find the median rainfall of Dispur
Obtain the Mode the data if mean rainfall is 23.4cm
Make Frequency distribution table from above graph.​

Answer 1

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Answer 2

Identify less than type og and more than type ogive from the given graph,

The curve 1 is less than ogive

And the curve 2 is more-than ogive.

(As, in less than ogive, the cumulative frequency (cf) increases.

() Find the median rainfall of Dispur

The point of intersection of less than ogive and more than ogive is the median.

So, we can obtain the median by drawing a perpendicular line from the point of intersection of less than ogive and more than ogive.

Hence we get,

Median rainfall of Dispur  to be 21 cm.

Obtain the Mode the data if mean rainfall is 23.4cm

As we know that,

3 Median = Mode + 2 Mean

Median = 21 cm

Mean = 23.4 cm

3 × 21 = Mode + 2 × 23.4

63 = Mode + 46.8

Mode = 16.2 cm

Make Frequency distribution table from above graph.​

The frequency distribution table for the graph is attached below along with the graph