Question

33. A2g uniform piece of Pt is used to Adsorption follows the Freundlich adsorption isotherm and graph is given as log 44 2 09 4 log P (atm) The total mass of H, gas (in g) that is adsorbed on given Pt piece when pressure is 4 atm is M. The M value of is 5​

Answer 1

Explanation:

C. Read these lines from the poem and answer the questions that follow.

1. -Two vast and trunkless logs of stone Stand in the desert. Near them, on the sand,

a. Who says these words and to whom?

b. What are the 'vast and trunkless legs of stone? What lies near them on the sand?

d. How does the poet describe it?

25 (8)

the

Answer 2

The value of M is 9.051 g.

Given:

log(x/m) = (1/n) log P + log k

To Find:

The value of M.

Solution:

The Freundlich adsorption isotherm is given as:

x/m = kp^(1/n)

where x is the mass of gas adsorbed on mass of the adsorbent, m is the mass of adsorbent used, P is the pressure of the gas, and k and n are constants.

Taking logarithm on both sides,

log(x/m) = (1/n) log P + log k

Comparing with y = mx + c, we get

y = log(x/m), x-axis

x = log P, y-axis

m = 1/n

c = log k

The graph given is as follows:

log(x/m) = 2.09 + 4 log P

Comparing with y = mx + c, we get

m = 4

c = 2.09

Substituting the given values of P and x/m, we get

log(x/m) = 2.09 + 4 log 4

log(x/m) = 4.09

x/m = 10^4.09

x/m = 9.051 g

Since the total mass of H2 gas adsorbed on the Pt piece when pressure is 4 atm is M,

M = x/m = 9.051 g

Therefore, the value of M is 9.051 g.

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