33.
ABCD is a rectangle of length 20 cm and breadth 10 cm. OAPB is a sector
of a circle of radius
10/2 cm. Calculate the area of the shaded region.
| Take a = 3:14]
20 cm
D.
с
Р
10 cm
B
А
10V2 cm
rectangular part segment
Answers
C is your answer.............
Given : ABCD is a rectangle of length 20 cm and breadth 10 cm. OAPB is a sector of a circle of radius 10√2 cm
To find : area of the shaded region.
Solution:
Area of Rectangle = 20 * 10 = 200 cm²
OA = OB =10√2
AB = 20 cm
AB² = OA² + OB²
=> OAB is right angle triangle at O
=> ∠AOB = 90°
Area of Sector OAB = (90/360) π (10√2)²
= (1/4)(3.14) 200
= 157 cm²
Area of Δ OAB = (1/2) * OA * OB = (1/2) * 10√2 * 10√2 = 100 cm²
area of the shaded region. = area of rectangle + area of Triangle OAB - area of Sector OAPB
= 200 + 100 - 157
= 143 cm²
area of the shaded region. = 143 cm²
Learn more:
in the given figure find the area of shaded region if AC is the ...
brainly.in/question/8348767
find the area of the shaded region if PAST is square of side 14cm ...
brainly.in/question/7353537
https://brainly.in/question/18829029
